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General => The Tailgate => Topic started by: Bills Custom Calls on December 27, 2008, 11:41:59 AM

Title: A Math Question
Post by: Bills Custom Calls on December 27, 2008, 11:41:59 AM
I need to know how to figure How many gallons of liquid are in a piece of 6 inch pipe 50 ft long

Can any one tell me how to figure this up or just tell me the gallons

Thanks in advance

Bill
Title: Re: A Math Question
Post by: weedwalker on December 27, 2008, 12:15:53 PM
One U.S. gallon is 231 cubic inches
A 6" pipe has a radius of 3"
Length 50' x 12 = 600 inches
The volume of a cylinder is  V=nr2h
R is the radius and H is the height (length)
The volume in your pipe is:

V = n32 x 600 =  :confused:

68.37 gallons  :confused:
Title: Re: A Math Question
Post by: THO Game Calls on December 27, 2008, 02:03:19 PM
It's closer to 73 1/2 gallons Bill.

V= Pi * (r^2*L)  or

3.1416 x 5400 (converted to inches) =  16964.64 / 231 (cubic inches in a gallon) = 73.44

Google it -

Al Woodard

Title: Re: A Math Question
Post by: coyote101 on December 27, 2008, 02:07:02 PM
I get 73.44 gallons.

pi X radius2 X height  = volume

3.14159 X 3 in.2 X 600 in. = 16964.6 cubic inches

16964.6 in.3 / 231 in.3 per gallon = 73.44 gallons

Pat

Edit: Looks like Al got here first with the same answer.
Title: Re: A Math Question
Post by: weedwalker on December 27, 2008, 02:10:27 PM
That's why i put one of these " :confused:" by my answer. Math ain't one of my best subjects.  :biggrin:
Title: Re: A Math Question
Post by: KySongDog on December 27, 2008, 02:14:58 PM
I got 73.4398


Edit:  Looks y'all beat me to it.   :eyebrownod:
Title: Re: A Math Question
Post by: CCP on December 27, 2008, 02:27:19 PM
6in O.D. or I.D  :laf:
Title: Re: A Math Question
Post by: alscalls on December 27, 2008, 02:49:06 PM
Quote from: CCP on December 27, 2008, 02:27:19 PM
6in O.D. or I.D  :laf:

:roflmao: :roflmao: Here we go again..... :laf:
Title: Re: A Math Question
Post by: FinsnFur on December 27, 2008, 02:54:20 PM
Leave it to the plumber to throw that in there?
Rich aint your toilet running or something?  :laf:
Title: Re: A Math Question
Post by: THO Game Calls on December 27, 2008, 02:57:02 PM
When you figure out the actual inside diameter of the pipe, go here

http://www.online-calculators.co.uk/volumetric/cylindervolume.php

Plug in the numbers and divide the result by 231

Al Woodard
Title: Re: A Math Question
Post by: Bills Custom Calls on December 27, 2008, 03:04:46 PM
Thanks guys
this was not a math test I was trying to figure out how many gallons of water in my water well

The well casing measurews 6 inches across  ID inside diameter
Title: Re: A Math Question
Post by: Rich on December 27, 2008, 03:34:56 PM
bnccont ,
If the well is dry, the amount of water in the well pipe is exactly zero.  :roflmao:
Title: Re: A Math Question
Post by: Bills Custom Calls on December 27, 2008, 04:03:53 PM
Quote from: Rich on December 27, 2008, 03:34:56 PM
bnccont ,
If the well is dry, the amount of water in the well pipe is exactly zero.  :roflmao:


Rich I am so happy you got that figured out  :roflmao:

Ok So here is the story

I am trying to keep from putting a 275 gal storage tank for water in the basement.The well is 160 ft deep
the water comes in at 130 ft the pump is set at 158 ft there is at least 50 ft of water in the well so that puts the
water 20 ft above where it comes in.I am not sure how many gals per minutes this well makes.The way I got it figured is if it can push the water up the pipe 20 ft higher then where it comes in it should be a pretty strong well.
I replaced the submersible water pump today to see if I can keep water in the 2 houses that are drawing off of it.
The pump I pulled out had the screen pretty much plugged up,so I figured the pump was getting hot due to the lack of water it was able to push.Now that the new pump is installed and water running we seem to have better water pressure and alot better volume.I hope this has cured the problem
Thanks for all your input